-4.9t^2+298t+185=0

Solution for -4.9t^2+298t+185=0 equation:

-4.9t^2+298t+185=0

a = -4.9; b = 298; c = +185;
Δ = b2-4ac
Δ = 2982-4·(-4.9)·185
Δ = 92430
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{92430}=\sqrt{9*10270}=\sqrt{9}*\sqrt{10270}=3\sqrt{10270}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(298)-3\sqrt{10270}}{2*-4.9}=\frac{-298-3\sqrt{10270}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(298)+3\sqrt{10270}}{2*-4.9}=\frac{-298+3\sqrt{10270}}{-9.8}
$